p = Patmosphere + rho g h
= 1.013*10^5 + 1030*9.81*10900
for part b divide that by 1.013*10^5
the deepest part of the ocean is 10,900 meters deep.
a) calculate the absolute pressure at that depth in units N/m^2. Use the mass density of sea water, 1030 kg/m^3. see part b for more info
b) one atmosphere of pressure is about 1.013 X 10^5 N.m^2. How many atmospheres is the pressure of part a?
1 answer