Decrease by 68.2% means amount remaining is 100-68.2 = ? = At
1/(A)t - 1/(A)o = kt
The decomposition reaction of A to B has a rate constant of 0.00923 M-1s-1:
A → 2B
If the initial concentration of A is 0.160 M, how long will it take for the concentration of A to decrease by 68.2%?
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