No but you started right.
ln(No/N) = kt
ln(0.05/N) = 1.2E-3(150) = 0.18 which is
ln(0.05/N) = 0.18
Now you want to know "the ln of what number is 0.18?" So you have 0.18 in your calculator, you punch the ex button and it returns 1.197 so
0.05/N = 1.197
N = 0.05/1.197 = 0.04177 which I would round to 0.042 (two s.f. in 1.2E-3)
The decomposition of an aldehyde solution in carbon tetrachloride is a first order reaction with a rate constant of 1.20 x 10-3 min-l. If we start with [aldehyde] = 0.0500 molar, what will the concentration be 150 minutes later?
1.20e-3(150) = 0.18
0.18(0.0500)=0.009M
The concentration is 0.009M. Did I do this correctly. Thank you.
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