The data below is for the reaction sequence A ⟶ B ⟶ C ⟶ D.
Elementary step ΔrH/kJ mol−1 Ea/kJ mol−1
A ⟶ B 24 48
B ⟶ C -12 36
C ⟶ D -48 24
how can i solve Ea forward, reverse, and rH given the above info?
3 answers
sorry that doesnt look clear. the 24, -12, and -48 are the ΔrH/kJ mol−1, and the 48, 36, 24 are for Ea/kJ mol−1
I'm sorry Kevin but I don't understand.
I can't tell what is forward and what is reverse.
By the way, if you have a problem lining up colums, I do this. It isn't perfect but at least it's an improvement.
....................A................B................C
I...................35...............0..................10
add.................................10..........................
C.................-10..............10.................10
E...................25...............10................10
The dots help space the html which is the code on the page.
I can't tell what is forward and what is reverse.
By the way, if you have a problem lining up colums, I do this. It isn't perfect but at least it's an improvement.
....................A................B................C
I...................35...............0..................10
add.................................10..........................
C.................-10..............10.................10
E...................25...............10................10
The dots help space the html which is the code on the page.
i see, thanks! tha'ts the thing - the question is asking to calculate Ea forward, Ea reverse, and rH. i got rH because i just added all of the ΔrH/kJ mol−1 and got the ans as -36. but am unsure how to find Ea forward and reverse. i think we have to draw a graph accurately to determine that, but im still not getting it
2 answers