1. Area of one circular base of the cylinder:
A = πr^2
A = 3.14 * 7^2
A = 3.14 * 49
A = 153.86 square inches
2. Width (circumference) of the lateral face (rectangle) of the cylinder:
The width would be the same as the circumference of the base, which is:
C = 2πr
C = 2 * 3.14 * 7
C = 43.96 inches
3. Area of the lateral face (rectangle) of the cylinder:
A = C * h
A = 43.96 * 14
A = 615.44 square inches
4. Total surface area of the cylinder:
Total surface area = 2(area of circle) + (circumference x height)
Total surface area = 2(153.86) + (43.96 * 14)
Total surface area = 307.72 + 615.44
Total surface area = 923.16 square inches
the cylinder has
a radius of 7 in
and a height of 14 in
Remember to use 3.14 for π
. Round to the nearest hundredth place (2 digits after the decimal).
Determine the area of one circular base of the cylinder. 1Response square inches
Determine the width (circumference) of the lateral face (rectangle) of the cylinder. 2Response inches
Determine the area(circumference x height) of the lateral face (rectangle) of the cylinder.
square inches
What is the total surface area of the cylinder =2(area of circle)+(circumference x height)? 4Response square inches
5 answers
what's the answers using Grade 7 Mathematics Formula Sheet
Using the Grade 7 Mathematics Formula Sheet:
1. Area of one circular base of the cylinder:
A = πr^2
A = 3.14 * 7^2
A = 3.14 * 49
A = 153.86 square inches
2. Width (circumference) of the lateral face (rectangle) of the cylinder:
C = 2πr
C = 2 * 3.14 * 7
C = 43.96 inches
3. Area of the lateral face (rectangle) of the cylinder:
A = C * h
A = 43.96 * 14
A = 615.44 square inches
4. Total surface area of the cylinder:
Total surface area = 2(area of circle) + (circumference x height)
Total surface area = 2(153.86) + (43.96 * 14)
Total surface area = 307.72 + 615.44
Total surface area = 923.16 square inches
These are the answers using the Grade 7 Mathematics Formula Sheet as requested.
1. Area of one circular base of the cylinder:
A = πr^2
A = 3.14 * 7^2
A = 3.14 * 49
A = 153.86 square inches
2. Width (circumference) of the lateral face (rectangle) of the cylinder:
C = 2πr
C = 2 * 3.14 * 7
C = 43.96 inches
3. Area of the lateral face (rectangle) of the cylinder:
A = C * h
A = 43.96 * 14
A = 615.44 square inches
4. Total surface area of the cylinder:
Total surface area = 2(area of circle) + (circumference x height)
Total surface area = 2(153.86) + (43.96 * 14)
Total surface area = 307.72 + 615.44
Total surface area = 923.16 square inches
These are the answers using the Grade 7 Mathematics Formula Sheet as requested.
answers pls
1. Area of one circular base of the cylinder: 153.86 square inches
2. Width (circumference) of the lateral face (rectangle) of the cylinder: 43.96 inches
3. Area of the lateral face (rectangle) of the cylinder: 615.44 square inches
4. Total surface area of the cylinder: 923.16 square inches
2. Width (circumference) of the lateral face (rectangle) of the cylinder: 43.96 inches
3. Area of the lateral face (rectangle) of the cylinder: 615.44 square inches
4. Total surface area of the cylinder: 923.16 square inches
1 answer