The curved artery can be approximated as a semicircular arch whose diameter is 4.9 cm. If blood flows through the aortic arch at a speed of 0.35 m/s, what is the magnitude (in m/s2) of the blood's centripetal acceleration?

Answer 1

d= 4.9 which means r=2.45cm. change that to meters, 0.0245m.
v=0.35
a=v^2/r
a=(o.35^2)/0.0245