Question

the curve y^2 = x(1-x)^2 between x = 0 and x =
1, rotates about the x - axis through 2pie
radians. Find the position of the centre of
gravity of the solid so formed.

Answer 1

PI, not pie!!!

The center of gravity is clearly on the x-axis, so we just need to find the x-coordinate.

Recall that

x-bar = (integral x*f(x) dx)/(integral f(x) dx)

Answer 2

i really wanna thank you sir-steve,but i really dont know that's the truth plz&plz can you at list start the work form me so that i know know the next step to take thanks bhai

Answer 3

just google the topic. You might start here:

https://www.whitman.edu/mathematics/calculus_online/section09.06.html

I'm sure your text has examples of finding the centroid.

If you are unsure about the shape, just see

http://www.wolframalpha.com/input/?i=y%5E2+%3D+x(1-x)%5E2

Answer 4

oooh thanks i guess that might help hopefully,i cant acess the url web address sir steve it doesn't wanna click i dont know why can u send it agn