Some call it witch of Maria Agnesi. She did not name it that, the name was a mistranslation of her work.
y'=dy/dx (1+x^2)^-1= -(1+x)^-2 * 2x
y'=-2x y^2
Put in x,y and you have it.
I am wondering..what was so difficult about this?
The curve below is called a witch of Maria Agnesi. Find an equation of the tangent line to this curve at the point (-2, 1/5).
y=1/(1+x^2)
2 answers
I just didn't have time to solve it, I had to run to class and now I only have a minute to enter all the correct answers, thank you
1 answer