area of cross-section of pipe
= π(30)^2 - π(1.4)^2
volume = 49(900π - 1.96π)
= 44003.96 cm^3
or appr 44000 cm^3
The cross section of a pipe of length 49cm.the thicknes of the pipe is 1cm4mm and the outer diameter is 30cm.find the volume of the pipe.
2 answers
Bt its ans 6166.16cm^3
1 answer