The crew of a garbage truck takes 5 hours to empty all the bins in one neighborhood on pickup day. The city assigned a second garbage truck to this neighborhood. During their training, it took the crew from the second truck 8 hours to empty all the bins.

A table showing Rate in part per hour, Time in hours, and Part of Bins Emptied. The first row shows First Truck and has, StartFraction 1 Over 5 EndFraction, t, and StartFraction 1 Over 5 EndFraction times t. The second row shows Second Truck and has, StartFraction 1 Over 8 EndFraction, t, and StartFraction 1 Over 8 EndFraction times t.

When the two crews start working together, what part of all the garbage bins will the first garbage truck empty?

0.6
0.5
0.7
0.4

1 answer

To determine what part of all the garbage bins the first garbage truck will empty when both crews work together, we first need to find their respective rates of working.

  1. First Truck Rate: The first truck empties all the bins in 5 hours. Therefore, its rate of work is: \[ \text{Rate}_{\text{First Truck}} = \frac{1 \text{ (all bins)}}{5 \text{ (hours)}} = \frac{1}{5} \text{ bins/hour} \]

  2. Second Truck Rate: The second truck empties all the bins in 8 hours. Thus, its rate is: \[ \text{Rate}_{\text{Second Truck}} = \frac{1 \text{ (all bins)}}{8 \text{ (hours)}} = \frac{1}{8} \text{ bins/hour} \]

  3. Combined Rate: When both trucks are working together, their combined rate is the sum of their individual rates: \[ \text{Combined Rate} = \frac{1}{5} + \frac{1}{8} \] To sum these fractions, we need a common denominator. The least common multiple of 5 and 8 is 40. We can rewrite the rates as: \[ \frac{1}{5} = \frac{8}{40} \quad \text{and} \quad \frac{1}{8} = \frac{5}{40} \] Now summing the two rates: \[ \text{Combined Rate} = \frac{8}{40} + \frac{5}{40} = \frac{13}{40} \text{ bins/hour} \]

  4. Time Taken Together: Let \( t \) be the total time they work together in hours to empty all the bins. Since they can empty all bins together in the combined rate, it takes: \[ 1 = \left(\frac{13}{40}\right) t \implies t = \frac{40}{13} \text{ hours} \]

  5. Part of Bins Emptied by the First Truck in \( t \): The first truck will empty: \[ \text{Part}{\text{First Truck}} = \text{Rate}{\text{First Truck}} \times t = \left(\frac{1}{5}\right) \times \left(\frac{40}{13}\right) \] Simplifying: \[ \text{Part}_{\text{First Truck}} = \frac{40}{65} \implies \frac{8}{13} \]

  6. Calculating the Equivalent Decimal Value: To find the approximate decimal value of \( \frac{8}{13} \): \[ \frac{8}{13} \approx 0.615 \]

Based on the options given (0.6, 0.5, 0.7, 0.4), the closest approximation is:

0.6.

Thus, the part of all the garbage bins that the first garbage truck will empty is approximately 0.6.