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The cost of taking a cab is $4 plus $0.75 per mile. This can be represented using the linear function c=0.75m+4 , where c is th...Question
The cost of taking a cab is $4 plus $0.75 per mile. This can be represented using the linear function c=0.75m+4
, where c is the cost per trip and m is the distance in miles. Graph the equation on a coordinate plane. Based on your line, what would the corresponding dependent variable be if you were to travel 4.5 miles? Round your answer to the nearest hundredth.
, where c is the cost per trip and m is the distance in miles. Graph the equation on a coordinate plane. Based on your line, what would the corresponding dependent variable be if you were to travel 4.5 miles? Round your answer to the nearest hundredth.
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Answered by
GPT-4o mini
To find the cost \( c \) when traveling 4.5 miles, we can use the given linear function:
\[
c = 0.75m + 4
\]
Substituting \( m = 4.5 \):
\[
c = 0.75(4.5) + 4
\]
Calculating \( 0.75 \times 4.5 \):
\[
0.75 \times 4.5 = 3.375
\]
Now, add this to 4:
\[
c = 3.375 + 4 = 7.375
\]
Rounding to the nearest hundredth gives:
\[
c \approx 7.38
\]
So, if you were to travel 4.5 miles, the corresponding dependent variable (the cost) would be approximately **$7.38**.
To graph the equation \( c = 0.75m + 4 \), you would plot points for different distances \( m \) and their corresponding costs \( c \). For example:
- At \( m = 0 \): \( c = 4 \) (the starting fee)
- At \( m = 1 \): \( c = 4.75 \)
- At \( m = 2 \): \( c = 5.5 \)
- At \( m = 3 \): \( c = 6.25 \)
- At \( m = 4 \): \( c = 7 \)
- At \( m = 4.5 \): \( c = 7.38 \)
- At \( m = 5 \): \( c = 8 \)
You would then draw a straight line through these points, illustrating how the cost increases linearly with distance.
\[
c = 0.75m + 4
\]
Substituting \( m = 4.5 \):
\[
c = 0.75(4.5) + 4
\]
Calculating \( 0.75 \times 4.5 \):
\[
0.75 \times 4.5 = 3.375
\]
Now, add this to 4:
\[
c = 3.375 + 4 = 7.375
\]
Rounding to the nearest hundredth gives:
\[
c \approx 7.38
\]
So, if you were to travel 4.5 miles, the corresponding dependent variable (the cost) would be approximately **$7.38**.
To graph the equation \( c = 0.75m + 4 \), you would plot points for different distances \( m \) and their corresponding costs \( c \). For example:
- At \( m = 0 \): \( c = 4 \) (the starting fee)
- At \( m = 1 \): \( c = 4.75 \)
- At \( m = 2 \): \( c = 5.5 \)
- At \( m = 3 \): \( c = 6.25 \)
- At \( m = 4 \): \( c = 7 \)
- At \( m = 4.5 \): \( c = 7.38 \)
- At \( m = 5 \): \( c = 8 \)
You would then draw a straight line through these points, illustrating how the cost increases linearly with distance.
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