9cows + 18goats = 9000
Divide the whole equation with 3
3cows + 6goats = 3000
the cost of 6 cows are same as cost of 8 goats. if cost of 9 cows and twice numbered goats is rs. 9000, then find the cost of 3 cows and 6 goats?
(Here , twice numbered goats means 9 * 2 = 18)
4 answers
Let cost of cow be x and goat be y
6x=8y(given)
9x+18y=9000
x+2y=1000
X=1000-2y
Equating value of x in next step we get
6000-12y=8y
6000=20y
So y = 300 than x = 400
So cost of 3x+6y= 1200+1800
3000 RS is the cost of 3 cows and 6 goats
VERIFICATION
9X+18Y= 9000
3600+5400= 9000
6x=8y(given)
9x+18y=9000
x+2y=1000
X=1000-2y
Equating value of x in next step we get
6000-12y=8y
6000=20y
So y = 300 than x = 400
So cost of 3x+6y= 1200+1800
3000 RS is the cost of 3 cows and 6 goats
VERIFICATION
9X+18Y= 9000
3600+5400= 9000
As it is given that 9x+3y=9000
So if we divide the whole equation by 3 on both sides we get that:
3x+6y=₹3000
Thanks for seeing my answer
So if we divide the whole equation by 3 on both sides we get that:
3x+6y=₹3000
Thanks for seeing my answer
Heya