The cost c of opening a day school for one day is partly constant and partly varries as the number of students n it costs shs 40000 to run the school wen they are 500 students and shs 64000 when they are 900 students form am equation for de cost c and the number of student m.

1 answer

treat it as if you had two ordered pairs (500,40000) and (900,64000)
slope = (64000-40000)/(900-500) = 24000/400 = 60
(it costs shs 60 per student)
cost = 60m + b , <------ relate this to y = mx + b
plug in the point (500,40000)
40000 = 60(500) + b
b = 10000

c = 60m + 10000