The cost and revenue functions for a certain production facility are:

Question

C(x) = {x^2} + 2\,\,{\rm{and}}\,\,R(x) = 2{x^2} - x, then the break-even points are ( - 1,3)\,\,\,{\rm{and}}\,\,\,(2, - 6).

Answer 1

false

Answer 2

those codes don't work here, I read that as:

C(x) = x^2 + 2
R(x) = 2x^2 - x

equate them:
2x^2 - x = x^2 + 2
x^2 - x - 2 = 0
(x-2)(x+1) = 0
x = 2 or x = -1

if x=2, y = 6
if x = -1, y = 3

you had (2,-6) , don't see how you got y = -6
C(x) can never be negative, you are adding +2 to a square of something.

Answer 3

False