The coordination number of the central atom in [Mn(CO)4Br2] is 6, as it is coordinated to six ligands (four carbon monoxide ligands and two bromine ligands).
The oxidation number of the central atom can be calculated by considering the known oxidation numbers of the other atoms and the overall charge of the molecule. In this case, the molecule is neutral, so the sum of the oxidation numbers of all the atoms must add up to zero.
Let's assign the oxidation number of carbon in carbon monoxide (CO) as +2, the oxidation number of bromine as -1 (expected for a halogen), and the oxidation number of oxygen as -2.
Since there are four CO ligands, the total oxidation number contributed by carbon is: 4 * (+2) = +8
Since there are two bromine ligands, the total oxidation number contributed by bromine is: 2 * (-1) = -2
Let's assign the oxidation number of the central atom as x.
To determine the oxidation number of the central atom Mn, we can set up the following equation:
(+8) + (-2) + x = 0
Simplifying the equation, we get:
+6 + x = 0
Subtracting 6 from both sides, we find:
x = -6
Therefore, the oxidation number of the central atom (Mn) in [Mn(CO)4Br2] is -6.
The coordination number and oxidation number of the central atom in [Mn(CO)4Br2] are ________ and ________, respectively
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1 answer