The distance formula between two points (x1, y1) and (x2, y2) is √[(x2-x1)^2 + (y2-y1)^2].
Using point A (5, 3) and point C (-1, -9), the distance between A and C is √[(-1-5)^2 + (-9-3)^2] = √[(-6)^2 + (-12)^2] = √[36 + 144] = √180 ≈ 13.4 units.
Therefore, the measurement closest to the distance between point A and C in units is 13.4 units.
The coordinates of the vertices of a rectangle are A (5, 3), B (5, -9), C (-1, -9), and D (-1, 3).
Which measurement is closest to the distance between point A and C in units?
13.4 units
10.8 units
15.9 units
6.8 units
1 answer