the period of sin(x) is 2π.
the period of sin(-π/3 x) is 2π/(π/3) = 6
You need to multiply by the amplitude.
You need to reflect in the x-axis, since sin(-x) = -sin(x)
so, the quarter points are
(0,0), (3/2,-5), (3,0), (9/2,5), (6,0)
see the graph at
http://www.wolframalpha.com/input/?i=5sin(-%CF%80%2F3+x)
The coordinates of the five quarter points for y=sin(x) are given below.
Use these quarter points to determine the y-coordinates of the quarter points of y=5sin(-π/3x).
(0,0)
(π/2,1)
(π,0)
(3π/2,-1)
(2π,0)
(Type ordered pairs. Type exact answers, using π as needed)
- Please show steps and answers because I want to learn it.
2 answers
Y=1/5cos (-5x)
0 answers