To find the distance between the wrist pin P and the center of the crankshaft C, we can use trigonometry.
First, let's draw a diagram to visualize the problem:
P
*|\
R *| \
* *| \
* θ *| \ 6.4in
* *| \
* *| \
* *| \
* *| \
* *| \
C__________*________*_______
We can see that the distance between P and C is the hypotenuse of a right triangle formed by the connecting rod (6.4 in) and the horizontal distance between P and C.
Using trigonometry, we know that:
cos(θ) = adjacent / hypotenuse
We can rearrange this equation to solve for the adjacent side:
adjacent = cos(θ) * hypotenuse
adjacent = cos(20°) * 6.4 in
adjacent ≈ 6.4 in * 0.9397
adjacent ≈ 6.03968 in
Therefore, the wrist pin is approximately 6.0 inches away from the center of the crankshaft.
The connecting rod from the piston to the crankshaft in a certain 2.0 L engine is 6.4 in. The radius of the crank circle is 2.8 in. If the angle made by the connecting rod with the horizontal at the wrist pin P is 20 degrees, how far is the wrist pin from the center C of the crankshaft? Round to the nearest tenth of an inch.
1 answer
1 answer