the concentration of urea (MW=60.0g/mol) in a soltuion prepared by dissolving 16g of urea in 39g of H2O is ____ molal

Answer 1

mols urea = grams/molar mass
m = mols/kg solvent = mols/0.039 = ?

Answer 2

moles of urea:16(g)/60(g/mol)=0.267(mol)
39(g)*1(kg)/1000(g)=0.039kg
m=0.267/0.039=6.846(mol/kg)

Answer 3

7
7
77
777