The concentration of a benzene solution prepared by mixing 12.0 g C6H6 with 38.0 g CCl4 is__________ molal.

Answer 1

moles C6H6 = grams/molar mass C6H6.

m = moles C6H6/kg solvent.

Answer 2

Thanks for the help, is this right?
12.0/78.12=0.1536

0.1536/0.038=4.04

Answer 3

Yup

Answer 4

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