divide numerator and denominator by t^3
C=(3/t^2 + 1/t^2)/(1+50/t^3)
as t>>>very large, then
C=(0/1)=0 which means the chem is gone.
The concentration C of a chemical in the bloodstream t hours after injection into muscle tissue is C=(3t+t)/(t^3+50)
a. determine the horizontal asymptote of the function and interpret its meaning in the context of the problem.
b. use a graphing utility to graph the function and approximate the time when the bloodstream concentration is greatest.
2 answers
A. C=0
This indicates that the concentration of the chemical into the muscle tissue eventually dissipates.
B. t= 4.5 hours
C. C < 0.355 when 0 ≤ t ≤ 2.72 hours and t > 8.03 hours.
These are the right answers trust me or don't, doesn't matter to me if you get the answers wrong.
P.S - That isn't really my name
Gotta Blast
This indicates that the concentration of the chemical into the muscle tissue eventually dissipates.
B. t= 4.5 hours
C. C < 0.355 when 0 ≤ t ≤ 2.72 hours and t > 8.03 hours.
These are the right answers trust me or don't, doesn't matter to me if you get the answers wrong.
P.S - That isn't really my name
Gotta Blast