if z = a+bi,
a+bi + 2i(a-bi) = 12 + 9i
a+2b + (2a+b)i = 12 + 9i
a+2b=12
2a+b=9
a = 2
b = 5
z = 2+5i
The complex number z satisfies the equation z+2iz*=12+9i. Find z giving your answer in the form x+iy.
5 answers
so you do a simultaneous equation by equating the variables?
I don't quite understand the second line
you didn't expand the brakets
you didn't expand the brakets
OOOOHHHHHH get it now!! thank you Steve!!
Nice when the light bulb turns on, isn't it?
1 answer