C3H8(g) + 5O2(g)⟶3CO2(g) + 4H2O(g)
mols C3H8 = grams/molar mass = 61.9/44 = estimated 1.3 but notice that's just an estimate.
Every mole C3H8 requires 5 mols O2; therefore, mols O2 needed = estimated 5*1.3 = 6.5
Grams O2 = mols x molar mass = approx 6.5 x 32 = ?
Post your work if you get stuck.
The combustion of propane may be described by the chemical equation
C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g)
How many grams of O2(g) are needed to completely burn 61.9 g C3H8(g)?
1 answer
1 answer