To determine the force required to slide the box at a constant speed, we need to consider the force of kinetic friction, since the box is already in motion.
The force of kinetic friction (\(F_k\)) can be calculated using the formula:
\[ F_k = \mu_k \cdot N \]
where:
- \(\mu_k\) is the coefficient of kinetic friction (0.3 for wood and paper in this case).
- \(N\) is the normal force, which is equal to the weight of the box if the box is on a horizontal surface.
Given that the weight of the box is \(40 , \text{N}\), we can substitute the values into the equation:
\[ F_k = 0.3 \cdot 40 , \text{N} = 12 , \text{N} \]
Thus, the force that must be applied to slide the box over the floor at a constant speed is 12 N.
So, the correct response is:
12 N