M*g = 550 N. = Normal force(Fn).
Fs = u*Fn = 0.16 * 550 = 88 N. = Force
of static friction.
Fap-Fs = M*a
Fap - 88 = M*0 = 0
Fap = 88 N. = Force applied.
The coefficient of static
friction between a skier and
the snow is 0.16, with a
coefficient of kinetic friction
of 0.13. The skier weighs
550N. How much force
directed parallel to the
horizontal surface is required
for the skier to start to move?
Known,
Us= 0.16
Uk=0.13
Wt=550N
Im not sure how to work the question out and was just looking for some guidance
1 answer
1 answer