Nvm I figured it out but I'm gonna answer it anyway in case someone else has the same question.
Create the free body diagrams for A and B, when you do and solve for Ft on B you find they're the same numbers (so Ft on both is 98).
Solve for Fg of A, so 9.8•5=49. Fg and Fn are 49.
Solve for Ff of A using Ff=μ•Fn. Therefore Ff=.2•49. Ff=9.8.
ΣF=m•a
ΣFx=Ft-Ff=m•a
ΣFx=98-9.8=5•a
88.2=5a
a=17.64m/s^2
the coefficient of kinetic friction between both blocks and the table is .200. determine the accelerations of blocks A and B each of which has a mass of 5.0kg
The diagram shows a table with two blocks labeled A and B on them. A is connected to a rope that goes over a pulley and off the left side of the table with the rope having a force of 98N. B is connected to a rope that goes over a pulley and off the right side and is connected to a 10kg block. A and B are not connected or touching.
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