The coefficient of friction b/n the Tyre of the car rotating around horizontal circulary road and the road way is 0.5; what would the minimum radius at which a car turn ahorizontal road when its speed is 15m/s? g=10m/s

Answer 1

Ac = m v^2/R

so side force from friction = m v^2/R

= .5 m g

v^2/R = .5 g
R = 2 v^2/g