The club was given materials to build 160 feet of fence. If they used the auditorium wall for one side of their garden, what size rectangle should they make to have the largest area? If w represents the width of the rectangle and is perpendicular to the auditorium wall, what is the largest value possible for w? Why?
2 answers
in these kinds of problems, the largest area is always achieved when the available fencing is divided equally among lengths and widths. In this case, the maximum area is found when the garden is 80x40.
How did you get 80x40?
1 answer