I assume you meant ACB rather than ACV.
Since the angles total to 180, we have for angle ABC,
180-(5x+1)-(3x+12.5) = 162.5-8x
That is all we know. You have given no side lengths, nor even any way to determine the actual angles. Knowing all the angles would not help, since we have no similar triangle to compare against.
the city council is planning a new city park on a triangular plot of land formed by three intersecting streets the designer placed the triangle on a grid to determine the side lengths and angle measures needed for the purchase and placement of a fence surrounding the park each unit on the grid is one inch which represents 20 feet of actual length. THe measure of angle CAB in the designer's diagram is (5x+1) degrees and the measure of angle ACV is (3x+12.5) degrees. What is the actual side lengths of the triangular plot of land?
9 answers
The city council is planning a new city park on a triangular plot of land formed by three intersecting streets. The designer placed the triangle on a grid to determine the side lengths and angle measures needed for the purchase and placement of a fence surrounding the park. Each unit on the grid is one inch which represents 20 feet of actual length. THe measure of angle CAB in the designer's diagram is (5x+1) degrees and the measure of angle ACB is (3x+12.5). Angle A is (6.8) Angle B is (11,1) and Angle C is (1,1. What is the actual side lengths of the triangular plot of land?
What is the type of triangle formed by the intersection of the three streets?
What is the type of triangle formed by the intersection of the three streets?
well, the side lengths are
CB=10
Note that A is halfway from C to B (6=(1+11)/2), so ABC is an isosceles triangle, and
AB=AC=√74
Now all you have to do is scale up the dimensions by a factor of 20'/1" = 240 to get the actual side lengths.
We weren't asked for the angles, but now it is clear that since ACB=ABC,
(3x+12.5) = 162.5-8x
You can solve for x and figure the actual degree measures.
CB=10
Note that A is halfway from C to B (6=(1+11)/2), so ABC is an isosceles triangle, and
AB=AC=√74
Now all you have to do is scale up the dimensions by a factor of 20'/1" = 240 to get the actual side lengths.
We weren't asked for the angles, but now it is clear that since ACB=ABC,
(3x+12.5) = 162.5-8x
You can solve for x and figure the actual degree measures.
For the first question I put The actual side length of AB and CA is 8,6 and BC is 10.
For the second question I put the triangle is isosceles because it has two equal sides which are Ab and CA.
Are these the right way to answer these questions?
For the second question I put the triangle is isosceles because it has two equal sides which are Ab and CA.
Are these the right way to answer these questions?
8.6*
The next question asks the amount of fencing needed to surround the city park
I got 14 and 37.58
I got 14 and 37.58
okay so how would we right this out now
how did you get 37.58 and what is the unit for that
The amount of fencing needed to surround the city park
1 answer