The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was 36.6 m long and it had a muzzle speed of 1.48 km/s. When the gun's angle of elevation was set to 49°, what would be the range? For the purposes of solving this problem, neglect air resistance.

asked by Renee

14 years ago

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1 answer

Range = 2(V^2/g)sin49cos49
= (V^2/g)sin98 = 2.21*10^5 m = 221 km

answered by drwls

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The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was 36.6 m long and it had a muzzle speed of 1.48 km/s. When the gun's angle of elevation was set to 49°, what would be the range? For the purposes of solving this problem, neglect air resistance.

1 answer

Range = 2(V^2/g)sin49cos49
= (V^2/g)sin98 = 2.21*10^5 m = 221 km

drwls · Answer

Range = 2(V^2/g)sin49cos49 = (V^2/g)sin98 = 2.21*10^5 m = 221 km