The circumference of a circle is calculated using the formula C = πd, where C is the circumference and d is the diameter.
Given that the diameter is 1/2 inch, we can substitute this value into the formula:
C = π * (1/2)
C = 3.14 * (1/2)
C = 3.14/2
To approximate the circumference, we can divide 3.14 by 2:
C ≈ 1.57 inches.
Therefore, the approximate circumference of a circle with a diameter of 1/2 inch is approximately 1.57 inches.
The circumference of a circle equals pi times the diameter. Using 3.14 to approximate pi, what is the approximate circumference in inches of a circle with a diameter of 1/2 in ?
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9/4 is close to the square root of what interger?
To find which integer the square root of 9/4 is close to, we can simplify the fraction first.
The square root of 9/4 is √(9/4), which can be further simplified as √9/√4.
The square root of 9 is 3, and the square root of 4 is 2.
So, √(9/4) is equal to 3/2.
Therefore, 9/4 is close to the square root of the integer 2.
The square root of 9/4 is √(9/4), which can be further simplified as √9/√4.
The square root of 9 is 3, and the square root of 4 is 2.
So, √(9/4) is equal to 3/2.
Therefore, 9/4 is close to the square root of the integer 2.
wrong
I apologize for the incorrect response. Let's find the correct integer that is closest to the square root of 9/4.
The square root of 9/4 can be simplified as follows:
√(9/4) = √9 / √4 = 3/2.
To find the integer closest to 3/2, we need to determine if it is closer to 1 or 2.
The absolute difference between 3/2 and 1 is |(3/2) - 1| = 1/2.
The absolute difference between 3/2 and 2 is |(3/2) - 2| = 1/2.
Both differences are the same, but since 3/2 is closer to 2, the integer closest to the square root of 9/4 is 2.
Therefore, the square root of 9/4 is close to the integer 2.
The square root of 9/4 can be simplified as follows:
√(9/4) = √9 / √4 = 3/2.
To find the integer closest to 3/2, we need to determine if it is closer to 1 or 2.
The absolute difference between 3/2 and 1 is |(3/2) - 1| = 1/2.
The absolute difference between 3/2 and 2 is |(3/2) - 2| = 1/2.
Both differences are the same, but since 3/2 is closer to 2, the integer closest to the square root of 9/4 is 2.
Therefore, the square root of 9/4 is close to the integer 2.
i just said wrong
Apologies for the previous incorrect response. Let's find the correct integer that the square root of 9/4 is close to.
The square root of 9/4 can be simplified as follows:
√(9/4) = √9 / √4 = 3/2.
To determine which integer the square root of 9/4 is close to, we can evaluate the decimal approximation of 3/2.
3/2 is equal to 1.5 in decimal notation.
Now let's find the integer that is closest to 1.5:
We can see that 1 is closer to 1.5 than 2. The absolute difference between 1 and 1.5 is 0.5, while the absolute difference between 2 and 1.5 is 0.5 as well. However, since the distance from 1 to 1.5 is smaller than the distance from 2 to 1.5, the closest integer to the square root of 9/4 is 1.
Therefore, the square root of 9/4 is close to the integer 1.
The square root of 9/4 can be simplified as follows:
√(9/4) = √9 / √4 = 3/2.
To determine which integer the square root of 9/4 is close to, we can evaluate the decimal approximation of 3/2.
3/2 is equal to 1.5 in decimal notation.
Now let's find the integer that is closest to 1.5:
We can see that 1 is closer to 1.5 than 2. The absolute difference between 1 and 1.5 is 0.5, while the absolute difference between 2 and 1.5 is 0.5 as well. However, since the distance from 1 to 1.5 is smaller than the distance from 2 to 1.5, the closest integer to the square root of 9/4 is 1.
Therefore, the square root of 9/4 is close to the integer 1.