The circular area of the drum is (9x^2+30x+25)pi. What is the smallest diameter it can have?

(9x^2+30x+25)
(3x+15) (3x+15)
3(x+5) 3(x+5)
9(x+5)
9x+45 <--------

2 answers

(9x^2+30x+25)PI
(3x+5) (3x+5)PI
(3x+5)^2 * PI=area
but area =PI r^2

r^2=(3x+5)^2
r= 3x+5
D=2r=6x+10
Thank you