The chemical formula for t-butanol is

Question

(CH3)3COH
Calculate the molar mass of t-butanol.
Round your answer to 2 decimal places

Answer 1

To calculate the molar mass of t-butanol, we need to sum the molar masses of all the atoms in its chemical formula \((CH3)_3COH\).

First, let’s identify the atoms and their respective counts in the formula:

- Carbon (C): There are a total of 4 carbon atoms (3 from CH3 groups and 1 from the COH group).
- Hydrogen (H): There are a total of 10 hydrogen atoms (3 × 3 from CH3 groups and 1 from the OH group).
- Oxygen (O): There is 1 oxygen atom.

Next, we will use the atomic masses of these elements:
- Carbon (C) = 12.01 g/mol
- Hydrogen (H) = 1.01 g/mol
- Oxygen (O) = 16.00 g/mol

Now we calculate the contributions to the total molar mass:
- Carbon: 4 atoms × 12.01 g/mol = 48.04 g/mol
- Hydrogen: 10 atoms × 1.01 g/mol = 10.10 g/mol
- Oxygen: 1 atom × 16.00 g/mol = 16.00 g/mol

Add these contributions together to obtain the molar mass of t-butanol:
\[ 48.04\: \text{g/mol} + 10.10\: \text{g/mol} + 16.00\: \text{g/mol} = 74.14\: \text{g/mol} \]

Therefore, the molar mass of t-butanol is \( 74.14 \) g/mol (rounded to 2 decimal places).