The charges 10micro C and -10 micro C are placed at a point A and B seprated by a distance of 10 cm. Find the electric field on the perpendicular bisector of ab at a distance of 12cm from its middle point.

Answer 1

distance from each = d = sqrt(5^2+12^2) = 13 cm = .13 meter

however we may notice that the component along the bisector will be zero due to the opposite signs of the charges. However that is no true of the component along the direction between charges

E = k q/.13^2 for each
multiply by 5/13 to get component along line