φ=ω₀t-εt²/2
ω =ω₀-εt
ω=0
ω₀=v/r
φ=2πN
ε =ω₀²/2φ =v²/2r²•2πN=
= v²/4πr²N=36²/4•π•0.3²•40=28.6 rad/s²
the car has wheels of radius 0.3 m and is travelling at a speed of 36 m/s in a straight line and the wheel now describes 40 revolution while the car is brought to rest;
calculate the wheels angular acceleration.
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