a. Lets change five percent to moles /liter. Assume in the dilute solution, the density is 1kg/liter
volume:1 liter, 1000g,
mass of vinegar: .05*1000=50g
moles/liter= 50/molmass*1=5/6=.73 check that.
So your are diluting it 17.5/.73 times, or 24times. That means one part conc acid, then 23 parts water.
So you are given 4L acid, so you need 23*4L water.
The cafeteria decides to save money by using concentrated acetic acid (CH3COOH at 17.5 mol/L) and diluting it with water toproduce vinegar (5.00% m/v aceticacid).
a) What is the concentration of vinegar in mol/L?b) What volume of vinegar can the cafeteria produce from a 4.00 L jug of concentrated acetic acid?c) How much water would they need to add to the concentrated acet
2 answers
and, always add acid to water.