The building is 16 by 12 feet so, to the nearest tenth of a foot what distance (x) fom the building should time place the 16-ft ladder so that the top of the ladder will be 12 feet above the ground?

Answer 1

X^2 + Y^2 = (16)^2.
X^2 + (12)^2 = (16)^2.
X^2 = (16)^2 - (12)^2 = 112.
X = 10.6 Ft.