204 = 17*12
2(17+12) = 58
The Browns installed 58 feet of fencing around a rectangular play yard. If the yard covers 204 square feet, what are its dimensions?
2 answers
2 L + 2 w = 58
so L + w = 29
and L=29-w
w (29-w) = 204
29 w - w^2 = 204
w^2 - 29 w + 204 = 0
w = [ 29 +/- sqrt(841-816) ] / 2
w = [ 29 +/- 5 ]/2
w = 34/2 = 17
L = 12 that works
or
L =17 and w = 12
so L + w = 29
and L=29-w
w (29-w) = 204
29 w - w^2 = 204
w^2 - 29 w + 204 = 0
w = [ 29 +/- sqrt(841-816) ] / 2
w = [ 29 +/- 5 ]/2
w = 34/2 = 17
L = 12 that works
or
L =17 and w = 12
1 answer