Vo = 60 km/h = 60,000m/3600s. = 16.7 m/s.
V^2 = Vo^2 + 2a*d.
V = 0, Vo = 16.7 m/s, a = -0.80 m/s^2, d = ?.
The brakes on a car permit it to decelerate at the rate of 0.80 m/s2. How much distance is required to stop this car when it is traveling at 60.0 km/hr?
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