The boy on the tower of height h = 10 m throws a ball a distance of x = 68 m, as shown. At what speed, in m/s, is the ball thrown?

Answer 1

I do not see the figure. If the ball is thrown horizontally, use equations of motion
u = initial vertical velocity = 0 if the ball was thrown horizontally
S = distance travelled, metres
t = time, seconds
g = acceleration due to gravity = 9.81 m/s²

S = ut + (1/2)gt²

Solve for time t.

At the same time, the ball has travelled x=68m at a uniform horizontal velocity of vh.
So vh=S/t

If the ball is not thrown horizontally, we need to see a description of the figure.