The bottom of a ladder is on horizontal ground.
The top of a ladder is leaning against a vertical wall.
Diagram: right angle triangle labelled height is h metres, bottom of triangle is labelled d metres and in between the labelled h and d metres there is a 90 degrees angle. There is an angle to the left of that also next to d which is labelled x.
Carrying on question:
The bottom of the ladder is d metres from the wall. The top of the ladder is h metres above the ground. The angle between the ladder and the ground is x degrees.
Some safety instructions say it is safe to climd the ladder when:
h=4d
a) Work out the value of x when h=4d.
My working out:
1)c^2=a^2+b^2
2)hypotenuse is c so it equals the h metres squared multiplied by the d metres quared.
I have no clue after that please help.
Part b of this question:
Some different safety instructions say the angle between the ladder and the ground should be 75 degrees. the ladder is moved so that x=75 degrees
How does this affect the height, h metres, of the top of the ladder above the ground?
My answer:
The angle is higher so the height is higher.
I am not really sure about part a and part b please help
2 answers
x = arctan(4) = 76°
for part b, h decreases, because x decreases.