To solve the system of linear equations given by:
- \( 4h + 4s = 107 \)
- \( 7h + 5s = 15 \)
let's first simplify the first equation by dividing everything by 4:
\[ h + s = 26.75 \quad \text{(Equation 1)} \]
Now we have:
- \( h + s = 26.75 \)
- \( 7h + 5s = 15 \)
We can express \( s \) in terms of \( h \) from Equation 1:
\[ s = 26.75 - h \quad \text{(Equation 2)} \]
Now we will substitute Equation 2 into the second equation:
\[ 7h + 5(26.75 - h) = 15 \]
Distributing the 5:
\[ 7h + 133.75 - 5h = 15 \]
Now combine like terms:
\[ 2h + 133.75 = 15 \]
Subtract 133.75 from both sides:
\[ 2h = 15 - 133.75 \] \[ 2h = -118.75 \]
Now, divide by 2:
\[ h = -59.375 \]
Now substitute \( h \) back into Equation 2 to find \( s \):
\[ s = 26.75 - (-59.375) \] \[ s = 26.75 + 59.375 \] \[ s = 86.125 \]
So the solutions are:
\[ h = -59.375, \quad s = 86.125 \]
However, negative prices do not make sense in this context. There may have been a mistake in the interpretation or constraints of the equations provided. Please double-check the original equations for any errors.