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The booster club is selling refreshments. The following system of linear equations models the concession stand prices. Let repr...Asked by loaf
The booster club is selling refreshments. The following system of linear equations models the concession stand prices. Let represent the cost of a hot dog and represent the cost of the soda. Write the answers in decimal form. Solve the system of linear equations.
4h+4s=10
4
ℎ
+
4
𝑠
=
10
7h+5s=15
7
ℎ
+
5
𝑠
=
15
(1 point)
h=$
ℎ
=
$
s=$
𝑠
=
$
Check answerRemaining
4h+4s=10
4
ℎ
+
4
𝑠
=
10
7h+5s=15
7
ℎ
+
5
𝑠
=
15
(1 point)
h=$
ℎ
=
$
s=$
𝑠
=
$
Check answerRemaining
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the system of linear equations given:
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
Let's simplify the first equation. We can divide everything by 4:
\[
h + s = 2.5 \quad \text{(Equation 1)}
\]
Now, we can express \( s \) in terms of \( h \):
\[
s = 2.5 - h \quad \text{(Equation 2)}
\]
Next, we will substitute Equation 2 into Equation 1:
\[
7h + 5(2.5 - h) = 15
\]
Expanding this gives:
\[
7h + 12.5 - 5h = 15
\]
Combine like terms:
\[
2h + 12.5 = 15
\]
Subtract 12.5 from both sides:
\[
2h = 2.5
\]
Now, divide by 2:
\[
h = 1.25
\]
Now that we have \( h \), we can find \( s \) by substituting \( h = 1.25 \) back into Equation 2:
\[
s = 2.5 - 1.25 = 1.25
\]
Thus, the solution is:
\[
h = 1.25, \quad s = 1.25
\]
Final answers in decimal form:
- \( h = 1.25 \) (cost of a hot dog)
- \( s = 1.25 \) (cost of a soda)
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
Let's simplify the first equation. We can divide everything by 4:
\[
h + s = 2.5 \quad \text{(Equation 1)}
\]
Now, we can express \( s \) in terms of \( h \):
\[
s = 2.5 - h \quad \text{(Equation 2)}
\]
Next, we will substitute Equation 2 into Equation 1:
\[
7h + 5(2.5 - h) = 15
\]
Expanding this gives:
\[
7h + 12.5 - 5h = 15
\]
Combine like terms:
\[
2h + 12.5 = 15
\]
Subtract 12.5 from both sides:
\[
2h = 2.5
\]
Now, divide by 2:
\[
h = 1.25
\]
Now that we have \( h \), we can find \( s \) by substituting \( h = 1.25 \) back into Equation 2:
\[
s = 2.5 - 1.25 = 1.25
\]
Thus, the solution is:
\[
h = 1.25, \quad s = 1.25
\]
Final answers in decimal form:
- \( h = 1.25 \) (cost of a hot dog)
- \( s = 1.25 \) (cost of a soda)
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