The bond enthalpy of the Br−Cl bond is equal to ƒ¢H�‹ for the reaction

Question

BrCl(g) �¨ Br(g) + Cl(g).
Use the following data to find the bond enthalpy of the Br−Cl bond.

Br2(l)--->Br2(g) ĢH=30.91 KJ/mol
Br2(g)--->2Br2(g) ĢH=192.9 KJ/mol
Cl2(g)---->2Cl(g) ĢH=243.4 KJ/mol
Br2(l) + Cl2(g)---->2BrCl(g) ĢH=29.2 KJ/mol


A. 219.0 kJ/mol
B. 203.5 kJ/mol
C. 14.6 kJ/mol
D. 438.0 kJ/mol
E. 407.0 kJ/mol