The board sandwiched between two other boards weighs 92.6 N. If the coefficient of friction between the boards is 0.587, what must be the magnitude of the horizontal forces acting on both sides of the center board to keep it from slipping downward? Answer in units of N.

Answer 1

mg=force friction=2*mu(forcehorizontal)
solve for force horizontal

I get mg/2mu

Answer 2

yay thank you!!