The blade of a windshield wiper moves through an angle of 90.0° in 0.31 s. The tip of the blade moves on the arc of a circle that has a radius of 0.59 m. What is the magnitude of the centripetal acceleration of the tip of the blade?

Answer 1

φ=90°=π/2
ω= φ/t
a= ω²R= φ²R/t²=π²•0.59/0.31²=60.6 m/s²