The bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the birds altitude. Give your answer to the nearest hundredth and remember the bird is descending.

1 answer

The bird descends from an altitude of 10 meters to an altitude of 3 meters in a time interval of 3 seconds. To find the rate of change of the bird's altitude, we divide the change in altitude by the change in time.

Change in altitude = 10 meters - 3 meters = 7 meters
Change in time = 3 seconds

Rate of change of the bird's altitude = Change in altitude / Change in time
= 7 meters / 3 seconds
= 2.333 meters per second (rounded to the nearest hundredth)

The quotient 2.333 can be interpreted as the bird descending at a rate of approximately 2.33 meters per second.