The biochemical conversion of Glucose, C6H12O6, into pyruvic acid, C3H4O3, is an important step in the TCA (Kreb’s) cycle which forms a part of the metabolic breakdown of glucose (to produce energy).
C6H12O6 (s) + O2 (g) → 2C3H4O3(l) + 2H2O (l)
glucose oxygen pyruvic acid water
Calculate the enthalpy change for this conversion given the following enthalpies of combustion:
1. C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (l)
ΔH1 = -2821 kJmol-1
2. C3H4O3 (l) + 5/2 O2 (g) → 3CO2 (g) + 2H2O (l)
ΔH2 = -1170 kJmol-1
I havent studied enthalpy change before my last lecture. I am expected to know how to work out enthalpy change however we were not taught how to do this during the lesson. I havent studied A level chemistry and am currently at university. I would appreciate if you could dumb it down for me. =] thanks
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