The bearings of ships A andB from Port P are 225° and 116° respectively.Ship A is 3.9km from ship B on a bearing of 258°.Calculate the distance of ship A from P

Answer 1

Draw the triangle PAB
∡B = 38°
∡A = 33°
side p = 3.9
So, ∡P = 109°
Using the law of sines,
b/sin38° = 3.9/sin109°
b = 2.54 km

Answer 2

We are not going to calculate this for you. Get a life or drop out.