first, it's theta, not Teta
second, I think you mean r or q, and not "Teta"
If the bearing of q from p is 250° then you have an isosceles triangle pqr so r is directly south of p: a bearing of 180°
If you meant that the bearing of r from p is 250°, then you need to adjust things. Post your work if you get stuck.
The bearing of Teta from p is 250 and the bearing of r from q is 160 degree. If q is equidistant from p and r , find the bearing of r from p.
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